can we determine the atomic weights the zinc and copper native this experiment? How? What other details is needed? Experiment AThe fixed of a copper turnings is determined. Warm the copper v excess sulfur. The product mass is determined.Result: mass of copper: 1.70g fixed of copper sulfide: 2.48gExperiment BThe massive of zinc is determined. Include sufficient 6M HCl come the zinc come dissolve all the zinc. Warmth the product ~ above the steam bath until many of the liquid was disappeared. ~ that warmth the product till the product looking somewhat pasty when hot. Weigh the product.Result: mass of zinc: 0.48g fixed of zinc chloride :1.02g

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As second data we require the atomic weights of Sulphur, Chlorine and Hydrogen.

Atomic weights

S = 32g/(mol)

Cl = 35.5g/(mol)

H = 1g/(mol)

`Cu_((s))+S_((s)) rarr CuS_((s))`

`Zn_((s))+2HCl_((aq)) rarr ZnCl_(2(s))+H_(2(g))`

Mole ratio

`Cu:CuS = 1:1`

`Zn:ZnCl_2 = 1:1`

permit the atomic load of Cu is Xg/(mol)...

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As second data we require the atomic weights that Sulphur, Chlorine and Hydrogen.

Atomic weights

S = 32g/(mol)

Cl = 35.5g/(mol)

H = 1g/(mol)

`Cu_((s))+S_((s)) rarr CuS_((s))`

`Zn_((s))+2HCl_((aq)) rarr ZnCl_(2(s))+H_(2(g))`

Mole ratio

`Cu:CuS = 1:1`

`Zn:ZnCl_2 = 1:1`

Let the atomic load of Cu is Xg/(mol) and also Zn is Yg/(mol).

Cu moles provided = `1.7/X`

Zn moles offered = `0.48/Y`

Cus produced = `2.48/(32+X)`

`ZnCl_2` created = `1.02/(Y+71)`

`Cu:CuS = 1:1`

`(1.7/X)/(2.48/(32+X)) = 1`

`1.7/X = 2.48/(32+X)`

`X = 69.743`

`Zn:ZnCl_2 = 1:1`

`(0.48/Y)/(1.02/(Y+71)) = 1`

`0.48/Y = 1.02/(Y+71)`

` Y = 63.11`

Atomic load of Cu obtaided from check = 69.743g/(mol)

Atomic eight that Zn obtained from test = 63.11g/(mol)

In genuine world;

Atomic load of Cu = 63.546g/(mol)

Atomic load of Zn = 65.409g/(mol)

So we deserve to conclude the there will certainly be some errors in the tests.

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