You are watching: Is it true that logloss evaluation metric can have negative values?
1) Which of the adhering to statement is true in complying with case?A) Feature F1 is an instance of nominal variable.B) Feature F1 is an example of ordinal variable.C) It does not belengthy to any kind of of the above category.D) Both of these
(B)Ordinal variables are the variables which has actually some order in their categories. For example, grade A should be take into consideration as high grade than grade B.
2) Which of the following is an instance of a deterministic algorithm?A) PCAB) K-MeansC) Namong the above
(A)A deterministic algorithm is that in which output does not readjust on different runs. PCA would certainly provide the same result if we run aacquire, yet not k-means.
(A)Y=X2. Note that, they are not only associated, yet one is a role of the other and also Pearkid correlation in between them is 0.
Which of the complying with statement(s) is / are true for Gradient Decent (GD) and Stochastic Gradient Decent (SGD)?In GD and SGD, you upday a collection of parameters in an iterative manner to minimize the error feature. In SGD, you have to run through all the samples in your training set for a solitary upday of a parameter in each iteration. In GD, you either use the whole data or a subset of training information to upday a parameter in each iteration. A) Only 1B) Only 2C) Only 3D) 1 and 2E) 2 and 3F) 1,2 and also 3
(A)In SGD for each iteration you select the batch which is mainly contain the random sample of information But in instance of GD each iteration contain the every one of the training observations.
Which of the following hyper parameter(s), as soon as boosted might reason random forest to over fit the data? Number of TreesDepth of TreeLearning RateA) Only 1B) Only 2C) Only 3D) 1 and also 2E) 2 and 3F) 1,2 and also 3
(B)Typically, if we rise the depth of tree it will reason overfitting. Learning rate is not an hyperparameter in random forest. Increase in the variety of tree will certainly cause under fitting.
Imagine, you are working through "Analytics Vidhya" and also you want to build a maker learning algorithm which predicts the number of views on the write-ups. Your evaluation is based on attributes prefer writer name, variety of posts written by the same writer on Analytics Vidhya in past and also a couple of other attributes. Which of the complying with review metric would you choose in that case?Median Square ErrorAccuracyF1 ScoreA) Only 1B) Only 2C) Only 3D) 1 and 3E) 2 and also 3F) 1 and 2
(A)You can think that the variety of views of articles is the continuous taracquire variable which fall under the regression difficulty. So, suppose squared error will be supplied as an testimonial metrics.
Below are the 8 actual worths of tarobtain variable in the train file.
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<0,0,0,1,1,1,1,1>What is the entropy of the tarobtain variable? A) -(5/8 log(5/8) + 3/8 log(3/8))B) 5/8 log(5/8) + 3/8 log(3/8)C) 3/8 log(5/8) + 5/8 log(3/8)D) 5/8 log(3/8) - 3/8 log(5/8)
Let"s say, you are functioning via categorical feature(s) and also you have actually not looked at the distribution of the categorical variable in the test data.You want to apply one warm encoding (OHE) on the categorical feature(s). What difficulties you may challenge if you have applied OHE on a categorical variable of train dataset? A) All categories of categorical variable are not present in the test dataset.B) Frequency circulation of categories is different in train as compared to the test datacollection.C) Train and also Test always have exact same distribution.D) Both A and BE) Namong these
(D)Both are true, The OHE will fail to encode the categories which is current in test however not in train so it might be among the primary obstacles while using OHE. The challenge provided in alternative B is likewise true you have to even more mindful while using OHE if frequency distribution doesn"t same in train and also test.
Let"s say, you are using activation attribute X in surprise layers of neural netoccupational. At a certain neuron for any type of given input, you get the output as "-0.0001". Which of the adhering to activation feature might X represent? A) ReLUB) tanhC) SIGMOIDD) Namong these