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This is college Physics Answers v Shaun Dychko. 0.4 kilograms that spaghetti has its temperature enhanced by forty 5 Celsius degree within 120 secs by this microwave and also the particular heat the spaghetti we are told is 3.76 times ten come the three joules every kilogram every Celsius degree. Now the question is what is the power of the microwave? and also so that"s walking to be the price at which heat is moved to the spaghetti. So the is Q is the amount of heat the spaghetti absorbs and divided by the time which us are offered 120 seconds and the warm that the absorbs is the fixed times particular heat times change in temperature. For this reason that"s 0.4 kilograms time 3.76 time ten to the three joules every kilogram every Celsius degree times 45 Celsius levels all separated by 120 seconds offers the power of 564 Watts. The following question asks for the soot of the microwaves and also so we take the power and also have to division it through the area end which the strength is took in and we"re told the it"s absorbed over a circular area with a given diameter. And so we"ll find the area of the Circle i m sorry is Pie time radius squared but due to the fact that we"re provided diameter fine substitute diameter separated by 2 in place of r and also that way our area is Pie time diameter squared over four. Therefore we"ll substitute that in for area and I"m multiply by that reciprocal rather of separating by a fraction. So that"s why you have the four on the peak here. So 4 times power separated by Pie times diameter squared. So it"s 4 times 564 Watts v what we calculated in component A divided by Pie time 20 centimeters written as time ten to the minus two meters and square that giving an soot of 1.80 times ten to the four watts every square meter. The following question asks for the toughness of the electric field in this electromagnetic wave and the intensity is speed of irradiate times permittivity of complimentary space time the electrical field stamin at its optimal squared end two. And also so we"ll settle for E subscript oh E naught and also we"ll perform that by multiplying both political parties by two over C Epsilon naught and also then we"ll take it the square root of both sides. And so we have actually the electric field at its peak equates to the square source of 2 times the intensity split by speed of light times permittivity of complimentary space. So it"s square source of 2 times 1.7953 times ten come the 4 watts per square meter that us calculated in component b division that through the rate of irradiate times permittivity of cost-free space and we gain 3680 Newton"s per coulomb is the peak electric field strength. Climate in part d, we room asked for the magnetic field strength, and also there"s two means we can have excellent it. This is one method and climate the other method would usage the average intensity formula and so on and so on but this is the simpler means to do it. For this reason we"ll main point both sides by B naught end c . And then we settle for, oops, and then we solve for B nothing . For this reason the magnetic field strength at its height is the electrical field toughness at its peak separated by speed of light. So the 3676.66 Newton"s per coulomb we"re making use of the unrounded version of this in order to avoid intermediate rounding error, and we division that by 3 times ten come the eight meter per second giving 1.23 time ten come the minus five Tesla.
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