The method I went about it was that the passage mentioned there to be unreacted zinc that was accumulated and weighed. I construed then the Iodine, the various other reactant, to be then provided up and also so to be the limiting reagent.

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Late come the party below but... Why weren't girlfriend swayed through iodide, due to the fact that (I think) prior to the reaction in question occurred, iodine to be converted to iodide?

Trying to number out why \"iodide\" isn't right because the very first step the the reaction is dissolving the iodine, which I assumed converted it to I-? Or am ns wrong to assume that?

Product had actually 2:1 ratio of iodine come zinc. 2g the each. Iodine is heavier because of this you understand it has less moles. Then you look at the 2:1 proportion of iodine to zinc and it borders the reaction not only by having less moles but even if it was same moles since it used twice together much.

Late come the party below but... Why isn't it iodide? They stated the very first step was dissolving the iodine, which i assumed expected it went to iodide (I-). Was the an not correct assumption?

I answered the concern by going ago to the passage. You dissolve iodine crystals (solute) in the methanol (solvent) giving a red-brown solution. Therefore far, no brand-new product has actually been formed. You then add the Zinc to the flask and also heat the mixture up. At the end, you have a yellow equipment (new product is formed between the zinc and also iodine). Within this yellow brown solution, there room still zinc pellets remaining which would suggest that the zinc remained in excess and also the iodine to be the limiting reagent.

Alternatively, you're given 2g the both iodine and also zinc and also the 2:1 proportion so you can do some math to number out which one is the limiting reagent.

Iodine is in its diatomic type as I2, it's no a salt with ions. Dissolve it won't rest apart the covalent bond between two iodine atoms, therefore it remains in systems as I2 however just dissolved. Then it reacts with zinc, reducing it to I- ions. Those ions are products, no reactants.

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