Which is an essential step in the alternate an approach for balancing equations in redox reactions?

A) denote the species of bonds uncovered in the molecules B) identify the rate at which reaction take ar C) determining the fifty percent reactions of chemical equations D) denote the temperature at which the reaction occurs


The correct answer is C. The half reactions that a oxidization reaction helps united state to watch the electron move occurring and also the charge balance in a reaction. We deserve to determine with introspection if atoms on the left hand side are the exact same as those on the best hand side in a chemical equation, however we would not be able to decipher how to balance fee without the fifty percent reactions.

You are watching: Which is an important step in the alternate method for balancing equations in redox reactions?

For instance, in the oxidation reaction,

It is clear the atoms room balanced

But v the fifty percent reactions

We need two electron on left hand side to balance the fee on both sides. This would provide us the reduction fifty percent reaction.

The other half reaction needs 3 electrons on best hand side to give us one oxidation half reaction.

But the electrons must balance because that both reactions so we multiply the oxidation fifty percent reaction by 2 and also the reduction half reaction by 3

Clearly the usage of fifty percent reactions has helped us figure the stochiometric quantities for this oxidation reaction.


The correct answer is C. The fifty percent reactions of a oxidization reaction helps united state to check out the electron move occurring as well as the fee balance in a reaction. We can determine through introspection if atoms on the left hand side room the very same as those ~ above the appropriate hand next in a chemical equation, yet we would not have the ability to decipher exactly how to balance charge without the half reactions.

For instance, in the oxidation reaction,

It is clear that atoms space balanced

But with the fifty percent reactions

We need two electron on left hand side to balance the fee on both sides. This would provide us the reduction fifty percent reaction.

The other fifty percent reaction demands 3 electrons on ideal hand side to offer us one oxidation fifty percent reaction.

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But the electrons should balance because that both reactions so we multiply the oxidation half reaction by 2 and also the reduction half reaction through 3

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Clearly the usage of half reactions has helped us number the stochiometric quantities for this redox reaction.

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determining the half reactions of chemical equations so the exactly answer is C

C - determining the half reactions of chemistry equations

Explanation:

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the price is C

Explanation:


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